[programmers] 카드 뭉치

문제 링크

https://school.programmers.co.kr/learn/courses/30/lessons/159994

프로그래머스

 

 

 

풀이

 

* 포인터 관련 문제 같음

 

내 풀이

def solution(cards1, cards2, goal):
    answer = 'Yes'
    n = 0
    m = 0
    for g in goal:
        if (g == cards1[n%len(cards1)]) or (g == cards2[m%len(cards2)]):
            if g == cards1[n%len(cards1)]:
                n += 1
            else:
                m += 1
        else:
            return 'No'

    return answer

 

딱 내가 원하던 풀이

def solution(cards1, cards2, goal):
    for g in goal:
        if len(cards1) > 0 and g == cards1[0]:
            cards1.pop(0)       
        elif len(cards2) >0 and g == cards2[0]:
            cards2.pop(0)
        else:
            return "No"
    return "Yes"